Hi Rich ! >The quick loop will equally be optimized away, as neither it nor >the memset have any observable effect.
What do you call observable? Replacing the content of a memory region by a constant value is an observable effect by itself. The only case I know is, filling an automatic variable at the end of a function, when result of that variable is not used afterwards. That is the compiler may optimize away the memory fill by it's subexpression optimizer. -- Harald _______________________________________________ busybox mailing list [email protected] http://lists.busybox.net/mailman/listinfo/busybox
