hello, indeed that looks wrong: it would be easy to invert but i have no setup to test. can you do that ?
just change: if [ -z "$(ip -6 route list | grep default)" ]; then into if ! [ -z "$(ip -6 route list | grep default)" ]; then (note the ! here) re, wh ________________________________________ Von: busybox <[email protected]> im Auftrag von Bhattiprolu RaviKumar <[email protected]> Gesendet: Montag, 1. Februar 2021 10:36:02 An: [email protected] Betreff: Question on udhcpc script All, We are using busybox to get DHCPv6 address. However, I am bit confused on the part of the script /etc/udhcpc.d/50default: wait_for_ipv6_default_route() { printf "Waiting for IPv6 default route to appear" while [ $IF_WAIT_DELAY -gt 0 ]; do if [ -z "$(ip -6 route list | grep default)" ]; then printf "\n" return fi sleep 1 printf "." : $((IF_WAIT_DELAY -= 1)) done printf " timeout!\n" } The print says "Waiting for IPv6 default route to appear". However the if statement is checking for "$(ip -6 route list | grep default)"to be null (-z check) which means default route is not present. In our case, after DHCP, default route gets setup and "$(ip -6 route list | grep default)"returns an entry starting with default and since check is -z, it continues in the loop and finally prints "timeout". I am confused here. Am I missing something here? regards, Ravi _______________________________________________ busybox mailing list [email protected] http://lists.busybox.net/mailman/listinfo/busybox
