Hi all,
I've decided to take some of my ancient C code and move into the C++
world. Per the recommendations here, I am using VC++ express.
I have found some odd behavior and was hoping someone here could explain it.
Below is my program. I made a few changes which affected the output
described below the source.
// CppTest3.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include "stdio.h"
using namespace std;
int main(int argc, _TCHAR* argv[])
{
cout << "Hello World From About" << endl;
cout << "The command you typed was \"" << (char *)argv[0] << "\""
<< endl;
if (argc == 1)
{
cout << "You have not supplied any command line arguments." <<
endl;
}
else if (argc == 2)
{
cout << "You have supplied " << argc - 1 << " command line
argument." << endl;
cout << "It is \"" << (char *)argv[1] << "\""<< endl;
}
else
{
cout << "You have supplied " << argc - 1 << " command line
arguments.";
cout << " They are: " << endl;
for (int loopctr = 1; loopctr < argc; loopctr++)
{
cout << "(" << loopctr << "): \"" << (char *)argv[loopctr]
<< "\"" << endl;
}
}
return 0;
}
When I start a new project I get the entry point _tmain() rather than
main(). This causes the argv[] values to be printed as a single char
rather than a string of chars, like so:
> cpptest3 test2 test2 test3
Hello World From About
The command you typed was "c"
You have supplied 3 command line arguments. They are:
(1): "t"
(2): "t"
(3): "t"
Now, when I change it to main(), I get different results. For argv[0],
"cpptest3", I cast the argv[0] as (char *)argv[0] but left the other
references uncast.
> cpptest3 test2 test2 test3
Hello World From About
The command you typed was "cpptest3"
You have supplied 3 command line arguments. They are:
(1): "00345105"
(2): "0034510B"
(3): "00345111"
It appears I am seeing the memory address of the variable, not the contents.
Now, when I cast all the references to argv[], I finally get the results
I was looking for:
> cpptest3 test2 test2 test3
Hello World From About
The command you typed was "cpptest3"
You have supplied 3 command line arguments. They are:
(1): "test2"
(2): "test2"
(3): "test3"
So, what is going on with _tmain() and cout? I'm, currently, clueless.
~Rick
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