--- Uma Maheswara Rao Lankoti <[EMAIL PROTECTED]> wrote:
>unary ++ operator is having higher priority than unary * operator.
s.......provided might be compiler dependent......
Unary operators appear before their operand and associate from right to left.
so *b++ is token(ed) as *(b++) which refers to some garbage value pointed out
by b++ (i.e in simple, the incremented address (value) of some data).
Pedro Izecksohn <[EMAIL PROTECTED]> wrote:
--- Uma Maheswara Rao Lankoti <[EMAIL PROTECTED]> wrote:
> for *ptr++ :
> unary ++ operator is having higher priority than unary * operator. so
> *ptr++ is equal to *(ptr++). ie, its pointing to the value next to
> previously pointing one.
Are you sure?
__________________________________________________________
Want to start your own business?
Learn how on Yahoo! Small Business.
http://smallbusiness.yahoo.com/r-index
Send instant messages to your online friends http://uk.messenger.yahoo.com
