As I am sure, you read in my reply that I stated that the
Guass-Jordan method is faster. However, the transpose of
the adjoint is an easier algorithm to code.

If you are interested in the Guass-Jordan algorithm then
look at the following link:
http://www.nrbook.com/a/bookcpdf.php.

Please read what I say carefully before attempting to
contradict me. In most situations, the size of a matrix is
not arbitrary (except in engineering and physics problems).


--- saurabh gupta <[EMAIL PROTECTED]> wrote:

> 
> HI Neha
>    
>   Thanks  , but its the transpose of Coadjoint matrix ,
> which gets complex as the size of the matrix increases.
>    
>   I was looking for some kind of algorithm if anyone has
> for the inverse of matrix
>    
>   thanks& regards
>   saurabh
> "Joseph A. Marrero" <[EMAIL PROTECTED]> wrote:
>           
> 
> --- neha lodha <[EMAIL PROTECTED]> wrote:
> 
> > hey, i think u want to find transpose of a matrix....
> > for this just interchange the rols of row and columns
> > in the loop..
> > like...
> > for(i=o;i<r;i++)
> > {
> > for(j=0;J<c;j++)
> > printf("%d",a[i][j];
> > }
> > the above prog will simply write the contents of the
> > matrix A.now for transpose:
> > for(i=0;i<c;i++)
> > {
> > for(j=0;j<r;j++)
> > printf("%d",a[i][j])
> > }
> > hope this code will help u....;
> 
> The transpose of a matrix is the inverse only for
> orthogonal matrices. Because the OP did not state he was
> dealing with an orthogonal matrix, that may not work.
> 
> http://en.wikipedia.org/wiki/Orthogonal_matrix
> 
> > 
> > sau1983in <[EMAIL PROTECTED]> wrote:
> > Hi
> > 
> > Can any one guide me the appoach fpr finding out the
> > inverse of a 
> > matrix in C. I am just new to the C 
> > 
> > any help is appreciated.
> > 
> > regards
> > SAurabh
> > 
> > 
> > 
> > 
> > 
> > 
> > ---------------------------------
> > Everyone is raving about the all-new Yahoo! Mail beta.
> 
> _________________
> Joseph A. Marrero
> http://www.l33tprogrammer.com/
> 
>
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http://www.l33tprogrammer.com/


 
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