Please tell the compiler you are using because i have found the resuly 
coming out as :
6
6
I suppose this behaviour to be compiler dependant. I am using Dev-C++ a GCC 
version for windows.
This must be so in Linux as well since it is also having GCC by default.
Regards,
Debasish


<html><DIV>
<P><FONT face="Lucida Handwriting, Cursive" color=#ff9900 
size=2>Karmennavava Dhikaraste, Maaphaleshu 
Kadaachanah</FONT></P></DIV></html>





From: manju arumugam <[EMAIL PROTECTED]>
Reply-To: [email protected]
To: [email protected]
Subject: Re: [c-prog] help in the logic
Date: Wed, 7 Feb 2007 12:46:21 +0000 (GMT)

Both statement having the i value is 6 only,
++i is pre increment and i++ is post increment,  what is the doubt in this


sharma_anish9188 <[EMAIL PROTECTED]> wrote:                       
            I cant understand the logic
  can anybody help me to under stand

  int i=5;
  printf("%d",++i); = 6
  printf("%d",i++); = 5

  how?

  [mod - I assume you mean only one of those printf()'s, not the two in 
series as you've presented it - have a look at 
http://www.google.com/search?hl=en&q=postincrement+preincrement+C+difference&btnG=Google+Search
 
- PJH]





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