--- Robert Ryan <[EMAIL PROTECTED]> wrote:
> I will go over that code again. i can't see any
> reason that it should give an answer like -20. that
> answer must have come from something else...........
>
> "Victor A. Wagner Jr." <[EMAIL PROTECTED]> wrote:
> At 18:21 2007-02-04, Robert Ryan wrote:
> ok, correct.............
> it was at the end of the messsage
>
>
> "Victor A. Wagner Jr." <[EMAIL PROTECTED]> wrote:
>
> At 10:33 2007-02-04, Robert Ryan wrote:
>
> what would make it look better.
>
> you mean correct?
>
>
>
> "Victor A. Wagner Jr." <[EMAIL PROTECTED]> wrote:
>
> At 18:48 2007-02-03, Robert Ryan wrote:
> int array_one[ 25 ];
> > > int *array_two = new int[ 25 ];
>
>
> if you wanted to total up the ints, how would you
> do it.
> for(int i=0; i<array_one; i++) {
> total += array_one [i];
> and then cout << "The total Is: " <<; }
> no, not even close
>
> what is "i<array_one" supposed to do?
>
> #include <iostream>
>
> #include <numeric>
>
> using namespace std;
>
>
> int main()
>
> {
>
> int array_one[25];
>
> /* some code to put stuff in array_one */
>
> int total = accumulate(array_one,
> array_one+25, 0);
>
> cout << "The total is: " << total <<
> endl;
>
> }
>
>
>
> [deleted]
>
> Victor A. Wagner Jr. http://rudbek.com
> The five most dangerous words in the English
> language:
> "There oughta be a law"
>
The values in array_one could be anything. It just
goes out and grabs memory, and the values are whatever
was in there when it was grabbed. To make some
meaning you could do:
int array_one[25] = {0};
which would initialize all values in the array to 0.
Ray
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