How about splitting words terminated by new line in text file (see attached
test.txt)?
I tried this, it works not perfect :
#include <stdio.h>
int main() {
FILE *fp;
int letter,i,k,j;
char myarray[10][5];
char mywords[30];
i=k=j=0;
if( ( fp = fopen( "test.txt", "r")) == NULL) {
puts("Cannot open the file");
exit( 0 );
}
while( ( letter = fgetc( fp ) ) != EOF){
mywords[i] = letter;
if( mywords[i] == '\n' ){
myarray[j][k]="\0";
i++;
j++;
k=0;
}
myarray[j][k++] = mywords[i];
}
fclose(fp);
printf("0 %s\n" ,myarray[0]);
printf("1 %s\n" ,myarray[1]);
printf("2 %s\n" ,myarray[2]);
}
Please help if you have time,
Regards,
Hermann
On 2/15/07, Sudhanshu Gupta <[EMAIL PROTECTED]> wrote:
This is ur solution...
For the sake of simplicity, i hav used arrays instead of pointers.
So plz forgive me if u r keen on using pointers.
well sometimes using of pointers as strings may cause some prob
as the data of variables in mem may get overwritten.
so i personally avoid using them.
#include <stdio.h>
#include <string.h>
int main()
{
char mywords[]="Hallo,Hi,Hai,Hey";
unsigned int i,j,k;
char myarray[4][10];
clrscr();
i=j=k=0;
for(i=0;mywords[i];i++){
if(mywords[i] ==','){
myarray[j][k]='\0';
i++;
j++;
k=0;
}
myarray[j][k++] = mywords[i];
}
printf("%s\n" ,myarray[ 0]);
printf("%s\n" ,myarray[ 1]);
printf("%s\n" ,myarray[ 2]);
printf("%s\n" ,myarray[ 3]);
getch();
}
Sudhanshu Gupta
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