At 12:10 2007-03-27, mr_gees100_peas wrote:
>--- In [email protected], "Victor A. Wagner Jr." <[EMAIL PROTECTED]>
>Opps I forgot to remove the asterics I still can't figure out the
>lenght of the array though.
I told you earlier that you would NOT be able to know (from inside
your program) how big arr3[0] and arr3[1] are
you have to keep youself, perhaps in another array
or switch to C++
>#include <stdio.h>
>#include <stdlib.h>
>
>int main(int argc, char *argv[])
>{
> char *arr1[] = {"john", "paul", "ringo"};
> char *arr2[] = {"apple", "oranges"};
> char **arr3[] = {arr1, arr2};
> printf("name: %s\n",arr3[0][1]);
> printf("arr size is %d\n",sizeof(arr3[0][0])/sizeof(char *));
> system("PAUSE");
> return 0;
>}
>wrote:
> >
> > At 15:48 2007-03-26, mr_gees100_peas wrote:
> > >Hi,
> > >
> > > I have the following string arrays.
> > >
> > >char *arr1[] = {"john", "paul", "ringo"};
> > >char *arr2[] = {"apple", "oranges"};
> > >
> > >char *arr3[] = {*arr1, *arr2};
> > >
> > >What I want to do is access the content of arrays 1 and 2 inside of
> > >array 3. How do I go about this? And no I can't use a two dimensional
> > >array.
> >
> > that's a very common way to create a 2D array, so you're using one
> > whether you want or not.
> > iirc, arr3[0][1] will be "paul"
> >
> > now for the problems... you have NO way of knowing (inside your
> > program) how many elements are in arr3[0] and arr3[1] which means you
> > can't tell that there are 3 Beatles and 2 fruits.
> >
> >
> >
> >
> > >To unsubscribe, send a blank message to
> > ><mailto:[EMAIL PROTECTED]>.
> > >Yahoo! Groups Links
> > >
> > >
> > >
> >
> > Victor A. Wagner Jr. http://rudbek.com
> > The five most dangerous words in the English language:
> > "There oughta be a law"
> >
>
>
>
>
>To unsubscribe, send a blank message to
><mailto:[EMAIL PROTECTED]>.
>Yahoo! Groups Links
>
>
>
Victor A. Wagner Jr. http://rudbek.com
The five most dangerous words in the English language:
"There oughta be a law"
