atya dev , Before telling u the Issue O wold like to Tell u some things 1 . Dont Try To return any locally declared variables to the Called Function, caz once the function execution completed those variables will be destroyed... as u know variables will be declared on Stack for a Function call . ex : dont use like. char str[512]; return str; instead u can use like char *str = new char[512]; ............... .............. return str ; is the correct code and make sure that once read the value u must destroy that variable otherwise it will be a memory Leak.2. if u create a vriable like char *str[3]; -- will not create 3 character pointers instead of 3 array of strings. in ur Code u wrie as printf(\"Enter the String\"); scanf(\"%s\",str+h); u r using the Array of pointers with allocating memory to Them. this is a wrong Code. If at all if u want to use a Pointer to store data need to allocate memory.LIke... char *str[3]; str[0] = new char[256]; like...ok. i think now U got the problem in UR Code...On Mon, 2 Apr 2007 14:15:08 +0100 (BST) [email protected] wrote I made changes in the code main (I had problem with this code ) ignore previooous mail --------------------------------------------------- The purpose of the code is to return array of strings variable to main I am giving input 3 strings in function call() these strings are stored in a variable \"str\" then that is returned to main, I want to print them in main.. if i give input as --------------------------- aaa bbb ccc ------------------------------ output is ------------------------ aaa garbage value garbage value --------------------------------- I want to know why garbage values are being printed.............. ----------------------------------here is the code ---------------------- #include char* call() { int k=3,h=0; char *str[3]; for(h=0;h { printf(\"Enter the String\"); scanf(\"%s\",str+h); } return *str; } int main() { int i=3,j=0; char *name[i]; *name=call(); for(j=0;j { printf(\"The string %d\",j); printf(\"%s \",name+j); } return 0; } --------------------------------- Heres a new way to find what you\'re looking for - Yahoo! Answers [Non-text portions of this message have been removed]
Regards Prashanth Kumar Chanda [Non-text portions of this message have been removed]
