--- In [email protected], "Indika Bandara" <[EMAIL PROTECTED]> wrote: > > yes, but the original question was to how to create a > function pointer which can hold any number of arguments > > for example; > typedef void (*foo)(int, ...); > void func1(int, ...); > void func2(int, float); > > foo f1 = func1; // OK > foo f2 = func2; // NOT OK > > what this shows(as i understand) is the type foo can 'only' > hold variadic functions. but since it can hold variadic > functions i was hoping that it should be able to hold a > function with a certain number of arguments.... > u got the point? > > so to say if somebody wanted a function pointer type that > can hold functions with any number of arguments then is it > impossible? <snip>
As far as I know the standards, yes. You can have one or more arguments, but not zero or more. Regards, Nico
