compiled with gcc/linux
no errors/warnings
int main()
{
int i=5;
char buf[i];
return 0;
}
is the compiler so smart that he checks i doesn't get changed and
accepts above??
interestingly, it says this when given -Wall
1.cpp: In function `int main()':
1.cpp:18: warning: unused variable `char buf[((i - 1) + 1)]'
--- In [email protected], Ray Devore <[EMAIL PROTECTED]> wrote:
>
> --- Indika Bandara <[EMAIL PROTECTED]> wrote:
> > is this ok? this works sometimes
> >
> > 1)
> > func(int i)
> > {
> > char buf[i];
> > // access buf until i
> >
> > }
> > usage:
> > func(5);
> >
> >
> > 2)
> > func()
> > {
> > int i = 5;
> > char buf[i];
> > // access buf until i
> >
> > }
> >
> >
> > will these not produce segfaults? then why?
> >
> >
> I don't see why they are not giving you compile errors
> since the size of an array is supposed to be a const
> or a literal, not a variable.
>
> When you say "until i" can you provide the code you
> are using for the loop? If you are using the value at
> buf[i] then you should be a segfault sometimes. It
> depends on whether you have control of that address or
> some other program does.
>
> Need more information.
>
> Ray
>
>
>
>
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