--- bharat garg <[EMAIL PROTECTED]> wrote:
> I think your program should give the "segmentation
> fault error" as u
> are trying to store higher capacity char array in
> lower......
>
NO, as has already been pointed out all that is being
done is assigning the value of a single pointer to all
values of the array of pointers.
Ray
> On 6/18/07, Titi Anggono <[EMAIL PROTECTED]>
> wrote:
> > Hi all,
> >
> > I want to create an array consisting strings, but
> I
> > don't know where I made those mistakes.
> >
> > Here is part of code
> > ==================
> > .....
> > char *arrayA[5]; /*name of array variable that
> > stores strings*/
> > char stations[10];
> >
> > i=0;
> > while(fscanf(fileopen,"%s",&stations) != EOF){
> > arrayA[i] = stations;
> > printf("%s\n",arrrayA[i]); //Print1
> > i++;
> > }
> >
> > fclose(ffileopen);
> >
> > for(i = 0;i < 5;i++){
> > printf("%s\n",arrayA[i]); //Print2
> > }
> > ==============================
> >
> > Print1 gives result what I want since it equals to
> > scan the data. But Print2 gives me wrong result,
> the
> > output is the last input of variable stations. For
> > example,
> > the output Print1 is
> > LAT1
> > LAT2
> > LAT3
> > LAT4
> > LAT5
> > but, the output of Print2 is
> > LAT5
> > LAT5
> > ..
> > ..
> > LAT5
> >
> > Thanks for any explanations.
> >
> > Titi
> >
> >
> >
> >
>
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> >
>
>
> --
> Bharat Garg
> Indian School of Mines
> Dhanbad
>
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