this is what I am working on
#include <iostream>
int add (int x, int y) {
int z;
z = x + y;
return (z);
}
int sub (int x, int y) {
int z;
z = x - y;
return (z);
}
int multi (int x, int y) {
int z;
z = x * y;
return (z);
}
int div (int x, int y) {
int z;
z = x / y;
return (z);
}
main ()
{
int i, j, k1, k2, k3, k4;
i = 10;
j = 20;
k1 = + (i, j);
k2 = - (i, j);
k3 = * (i, j);
k4 = / (i, j);
cout("The result of k1, k2, k3 ,k4 is: \n", k1, k2, k3, k4);
}
Thomas Hruska <[EMAIL PROTECTED]> wrote: Robert Ryan wrote:
> actually, i am trying to get this done in C++. I should have made this in
> C++, what was i thinking
>> [email protected] wrote:
>>> #include <stdio.h>
>>>
>>> int add (int x, int y) {
>>> int z;
>>> z = x + y;
>>> return (z);
>>> }
>>> main ()
>>> {
>>> int i, j, k;
>>> i = 10;
>>> j = 20;
>>> k = add(i, j);
>>> printf ("The value of k is %d\n", k);
>>> }
>>> how do you change the above code to the following
>>>
>>> + (2, 6)
>>> - ( 2, 6)
Assuming you mean that you want to do something like:
k = operator+(2, 6);
Adding two 'int's is a primitive operation. You can't overload
operators for primitives. That's an ANSI C++ Standard restriction.
--
Thomas Hruska
CubicleSoft President
Ph: 517-803-4197
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