--- In [email protected], Mohan S N <[EMAIL PROTECTED]> wrote:
>
> --- Ananth <[EMAIL PROTECTED]> wrote:
>
> > Thomas Hruska <[EMAIL PROTECTED]> wrote:
> > > parrot_rabbit4u wrote:
> > > > --- In [email protected], senthil kumar
> > <blackdiamonds2007@>
> > > > wrote:
> > > >> #Iinclude<iostream.h>
> > > >> #include<conio.h>
> > > >> main()
> > > >> {
> > > >> int a,b,c;
> > > >> clrscr();
> > > >> cout<<"enter the number:";
> > > >> cin>>a>>b;
> > > >> c=a-(-b);
> > > >> cout<<"The add value:"<<c;
> > > >> getch();
> > > >> return 0;
> > > >> }
> > > >>
> > > >> ur program will definetly work with out using '+' operator.
> > > > thanks for ur this idea.
> > >
> > > This is fundamental math. Of the lightweight elementary school
> > 'Algebra
> > > I' variety. I still don't know why the OP thought they needed to
> > do
> > > this...
> >
> > To answer a trick question?
> > If learning C++, to impress friends and classmates?
> > Should be one of the two.
>
> Le me throw in my 2p too...
>
> Putting a+b as a - ( -b ) is not impressive.
Hmmm... I think it was +b sign being replaced by (-(-(b)). Why would
that change anything? I did not quite get it. I assume replacing +
with -- above does not modify the value of b in any way. Does it?
~Saurabh
> See this:
>
> for(i=0;i<b;i++){
> a++;
> }
>
> OR
>
> while(b){
> a++;
> b--;
> }
