On Mon, 15 Oct 2007, s b wrote:
> so for i have this code but i dont know how ot make it say 99.99 = ninty nine
> point ninty nine
> when i input it
>
> #include<stdio.h>
> #include<string.h>
> #include<iostream.h>
> int digit;
> int main(void)
> {
> printf("Please enter a number between 0 and 99.99: \n");
> scanf("%d");
You need to read a float. Decimal won't work.
Once you have your float, e.g. x=32.67, you need to split it into digits.
I think it's easiest just to multiply by 100 and convert to an int.
Then use
x%1000=267
so
x-(x%1000)=3000
or
(x-(x%1000))/1000=3
Keep using this method to split x into single digits
E.g.
3
2
6
7
Then use this single digit in your switch below. (You also need a switch
for the tens and one to handle values less than 20).
> switch(digit)
> {
> case 0: printf("Zero");
> break;
> case 1: printf("One");
> break;
> case 2: printf("Two");
> break;
> case 3: printf("Three");
> break;
> case 4:printf("Four");
> break;
> case 5:printf("Five");
> break;
> case 6:printf("Six");
> break;
> case 7:printf("Seven");
> break;
> case 8:printf("Eight");
> break;
> case 9:printf("Nine");
> break;
> case 11:printf("Ten");
> break;
> case 12:printf("Three");
> break;
> default: printf("Just a Test");
> printf("%d \n", digit);
> }
> }
