--- In [email protected], "johmgolden051500" <[EMAIL PROTECTED]> wrote: > > --- In [email protected], "John Monte" <johns_goldens@> wrote: > Ok if you type in the following > void main () > { > bit > } > The word bit will turn blue which indicate it is some type > of data type. I have one book that it shows is as bit 1 bit > long and the comments reads it as boolean value but it does > not shows any example of it. What I am looking to do is > the following. > unsigned char i; > unsigned char flag; // using the varible each flag bit > /* to indicate a flag */
First it's a very bad idea to use C++ style comments in C programs; if you program in C++, then use the // style, but if you work with C, then solely use /* and */ to enclose comments, nothing else. > if (flag && 1) ; when flag,0 = 1 then I will increment else i = 10 > i++; > else > i = 0x0a; > I want to use each bit of flag for some type of flag in my > prgram. When I try the above code and when flag bit 0 = 0 it > will not go to the else statement. <snip> Very clear; you have inserted an empty statement (namely a semicolon) after the condition if (flag & 1) The semicolon there will tell the compiler that there is an empty statement to be executed; so the "i++;" will always be executed, and then the "else" is "dangling" because there's no valid "if" before. So actually your compiler shouldn't compile this at all. Furthermore: do you work with Turbo C++? Bad idea because it doesn't understand ANSI C or ANSI C++; it's far too old for modern standards. Regards, Nico
