after much thought I got this problem solved
Robert Ryan <[EMAIL PROTECTED]> wrote: I am still
working on this problem.. it does take a bunch of thought....
thanks
Robert Ryan <[EMAIL PROTECTED]> wrote: does
anyone have any idea.
using get_Roman_token() the result should look like
II.+III. =5
IX.-II. =7
IV.*XI. =44
The result I get is:
vi Hw3#6.cpp
g++ Hw3#6.cpp
./a.out
Enter a Roman Numeral to be converted to a decimal: II. + II.
1
That is not a Roman numeral.
#include<iostream>
using namespace std;
int get_Roman_token() { };
int roman_to_int(char c)
{
char roman = c;
roman = toupper(roman);
if (roman == 'I') return 1;
else if(roman == 'V') return 5;
else if (roman == 'X') return 10;
else if (roman == 'L') return 50;
else if (roman == 'C') return 100;
else if (roman == 'C') return 100;
else if (roman == 'D') return 500;
else if (roman == 'M') return 1000;
else
{
cout << "That is not a Roman numeral." << endl;
return -1;
}
}
int main()
{
char Roman; int value, c1, c2, first, second;
cout <<"Enter a Roman Numeral to be converted to a decimal: ";
while(cin >> Roman)
{
int temp = roman_to_int(Roman);
if (temp > 0)
cout << temp << endl;
cin >> c1;
if(c1== '.')
return 0;
else
first = roman_to_int(c1);
cin >> c2;
if(c2 == '.')
{
cin.putback(c2);
return first;
}
else
second = roman_to_int(c2);
if (second > first)
return second - first;
else
cout << "Enter a Roman Numeral: ";
while(cin)
{
int temp = get_Roman_token() ;
if (temp != 0 )
value = value + temp;
else
{
cout<<value;
int value = 0;
}
}
}
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