Hello All,
A few days back I attended Huawei Interview where the following code's output
was expected:
unsigned char i;
for(i=0;i<2000;i++)
printf("\t%d",i);
A simple thinking gives the output to be :
values from 0 to 255.
When I checked it out on my Dev-C++ it showed counting exactly up to 2000.
Now my doubt it if a character variable occupies one byte then it should count
upto 255 only then it should overflow. Thus the result should be either
counting upto 255(and stop) or ending in an infinite loop counting each time up
to 255. Then why and how it is counting uoto 2000 (exactly).
Again in a forum it was asked to give the output of the following codes ::
unsigned i;
i=100*400;
printf("\n%d\n",i);
Strangely again, the output was exactly 40000as opposed to + 32767 or showing
any sort or overflow, since the range of unsigned int ranges from- 32767 to
32768.
Now my question is how the compiler manages to tackle such situations, I mean
what mechanism does the compiler the aplies in such a situation...
Regards,
Debasish
Karmennevaya Dhikaraste, Maaphaaleshu Kadaachanah
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