--- In [email protected], "titli_juit" <[EMAIL PROTECTED]> wrote:
>
> char *p="asdaddaddA";
> printf("%d",sizeof(p));
>
> the ans is 2 or 4 depending on compiler. can u plzz expalin why it
> would be so? i think that the sizeof operator on a pointer type
> variable returns size of the type of object pointer points to.
>
Hi,
run this program:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void main(void)
{
char a[]="hello world";
char *j="hello world";
float *p;
int *k;
double *q;
clrscr();
printf("pointer size=%d",sizeof(k));
printf("\npointer size=%d",sizeof(j));
printf("\npointer size=%d",sizeof(p));
printf("\npointer size=%d",sizeof(q));
printf("\n\ninteger size=%d",sizeof(*k));
printf("\nchar size=%d",sizeof(*j));
printf("\nfloat size=%d",sizeof(*p));
printf("\ndouble size=%d",sizeof(*q));
getch();
}
the surprising thing is that the pointer size for all variable is the
same. While when we call "*[variable name]", sizeof basically returns
the size of the variable pointed by the pointer.
I Hope this might solve your query.
regards,
Kumail
