debasish deka wrote:
> Wish you a Good Day,
> In the following code :
> struct mystruct {
> char a;
> int b;
> short c;
> char d;
> };
>
> int main(int argc, char *argv[])
> {
>
> char ch;
> int i;
> struct mystruct foo[3];
>
> printf("&foo[0]=%p\t&foo[1]=%p\t&foo[2]=%p\t&ch=%p\t&i=%p\n", \
> &foo[0], &foo[1], &foo[2], &ch, &i);
>
>
> system("PAUSE");
> return 0;
> }
>
>
> The output was :
> &foo[0]=0022FF30
> &foo[1]=0022FF3C
> &foo[2]=0022FF48
> &ch=0022FF6F
> &i=0022FF68
>
>
> Now my doubt is, char ch and int i being declared earlier to struct mystruct
> foo[3] are assigned lower memory location compared to the array of
> structures. Why does it happen like this ?
>
> With Regards,
> Debasish
Your compiler decided to do that. Stacks typically "grow downward" but
there is no guarantee of that.
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Thomas Hruska
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