#include<stdio.h>
#include<string.h>
int main()
{
char *s1[7]="hello1"; // 5
char *s2[7]="hello2"; // 6
{
strcpy(s1, s2); // 8
printf("%s\n", s1, s2);
}
}
7-26C++.cpp: In function `int main()':
7-26C++.cpp:5: invalid initializer
7-26C++.cpp:6: invalid initializer
7-26C++.cpp:8: cannot convert `char**' to `char*' for argument `1' to `char*
strcpy(char*, const char*)'
--- On Sat, 7/26/08, Oliva Lukas <[EMAIL PROTECTED]> wrote:
From: Oliva Lukas <[EMAIL PROTECTED]>
Subject: Re: [c-prog] Segmentation fault
To: [email protected]
Date: Saturday, July 26, 2008, 11:11 AM
Maybe to be more specific,
you should use array of chars for string representation, so for "hello",
char s1[7] = "hello";
should be used.
Lukas Oliva
On Fri, Jul 25, 2008 at 07:42:16PM -0700, Thomas Hruska wrote:
> Robert Ryan wrote:
> > #include<stdio. h>
> > #include<string. h>
> > int main()
> > {
> > char *s1="hello1" ;
> > char *s2="hello2" ;
> > {
> > strcpy(s1, s2);
> > printf("%s\n" , s1);
> > }
> > }
> >
> > [EMAIL PROTECTED] ~/CSSp08]$ ./a.out
> > Segmentation fault (core dumped)
>
> That is because the memory of s1 and s2 are _read only_. The pages are
> flagged by the OS as read-only. Attempting to write to a read only page
> results in an exception being raised. In other words, accept that the
> above is something you should NOT do and live with it.
>
> (There are ways to force pages of RAM to be read-write under all major
> OSes, but such is outside the scope of this group, the methods are
> non-ANSI Standard, and involve advanced OS topics where you only use
> such methods when you really, truly know what you are doing not just
> with C/C++ but with the OS itself).
>
> --
> Thomas Hruska
> CubicleSoft President
> Ph: 517-803-4197
>
> *NEW* MyTaskFocus 1.1
> Get on task. Stay on task.
>
> http://www.CubicleS oft.com/MyTaskFo cus/
>
[Non-text portions of this message have been removed]
