On Sun, 2008-07-27 at 16:31 +0530, saurabh jain wrote: > Hi all, Hi!
> In the following line: > "W64& mem = *(W64*)(W64)addr;" > addr is W64 too? then the cast is unnecessary. > mem is a reference to addr or location pointed to by addr? mem is a reference. > Is it not equal to W64& mem = addr? > Yes, if addr is W64. Regards, Sebastian.
