"hamoodmeero" <[EMAIL PROTECTED]> wrote:
>
> WELL ALL I WROTE IN THE TEST QUESTION IS THIS,
> SO PLEASE CAN U CORRECT ME AND TELL ME WHERE
> IS THE MISTAKE ?....THNXX :
For someone dealing in secrets, you sure make a lot of noise!
If you can avoid holding the shift or caps locks when coding,
please do the same with your emails.
> #include<stdio.h>
>
> int main()
> {
> char alpha[26]=
>
{'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q',
> 'R','S','T','V'.'U','W','Y','Z'}
> char a[26]=
>
{'J','P','F','L','X','O','C','M','S','E','B','N','G','Q','D','R','U',
> 'V','W','K','T','Y','A','H','I'}
> char code[60];
> printf(" ENTER THE CODE : ");
> scanf("%s",&code);
> for(int i=0 ; i<26 ; i++)
> if(alpha[i]==a[i])
Why would this condition be true? Look at your initialisation...
alpha[ 0] == 'A' a[ 0] == 'J'
alpha[ 1] == 'B' a[ 1] == 'P'
...
alpha[26] == 'Z' a[26] == 'I'
You're asking if 'A' == 'J', or if 'B' == 'P', etc...
> code[alpha];
This is a valid statement, but a useless one since it
has no side effects. It doesn't assign a value or
perform any output.
>
> return 0 ;
> }
--
Peter
