Hi,
Check this pice of code for dynamic memory allocation for twodimensional
array
#include <stdio.h>
float **bidimen_alloc(int row, int col);
main()
{
int i;
float **ptr = NULL;
ptr = bidimen_alloc(10 ,10);
if (ptr == NULL) {
printf("ERROR\n");
exit(1);
}
ptr[0][0] = 10.20;
ptr[9][9] = 100.20;
printf("%f %f\n", ptr[0][0], ptr[9][9]);
}
float **bidimen_alloc(int row, int col)
{
int i = 0;
float **mem = NULL;
mem = (float **)malloc(row * sizeof( float*));
if (mem == NULL)
return NULL;
for (i = 0; i < row; i++) {
mem[i] = (float *)malloc(col * sizeof(float));
if (mem[i] == NULL) {
while (--i > 0)
free(mem[i]);
return NULL;
}
}
return mem;
}
Thanks & Regards,
Rajath N R
--- On Mon, 10/20/08, Miguel Caro <[EMAIL PROTECTED]> wrote:
From: Miguel Caro <[EMAIL PROTECTED]>
Subject: [c-prog] Please help again, bidimensional dynamic array as a global
variable
To: [email protected]
Date: Monday, October 20, 2008, 6:41 PM
Hello everybody,(Hello Tyler)
Well, some days ago, i was asking about how to define a bidimensional
dynamic array as a global variable to use as incoming variable in a
function, but i could not solve the problem.
Let us see , for example in a part of a programm my problem:
#include<iostream>
...
using namespace std;
float a[10][10];// in this place i wish define a bidimenional dynamic array
agian: how to do it?
...
//follow the function
float suma(int k, float a[][10])
{
float s=0;
for (int i=1;i<k;i++)
for (int j =1;j<k;j++)
s=s+a[i][j];
return (s);
}
int main()
{
...
suma(k,a);
...
}
But instead defining an static bidimensional array a[10][10], to use after
as an incoming variable in a function, i wish to define it as dynamic
array(to work with a huge array for example(a[500] [500]) )
would you like to help me?
--
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