The line
main ()
declares "main" as a pointer to the function main()
just as "array_name" is a pointer to the first element of the array
array_name[]
and is the same as &array_name[0] which means "address of first array element
of array called array_name".
From http://en.wikipedia.org/wiki/Main_function#C_and_C.2B.2B
In C and C++, the function prototype of the main function is one
of the following:
int main(void);
int main();
int main(int argc, char *argv[]);
Therefore "main" is an int.and
printf("Main: %d", main);
Will print the address of main.
mcb
----- Original Message -----
From: Manoj Vivek
To: [EMAIL PROTECTED]
Cc: [email protected]
Sent: Friday, October 31, 2008 11:48 AM
Subject: Re: [c-prog] obveious
what are you saying.. I can't understand.. ... Where is main declared... How
can it be printed as a integer using %d..... You are saying it is declared if
it is declared what is the data type...
Brett McCoy wrote:
> On Fri, Oct 31, 2008 at 1:11 PM, Manoj Vivek < vivek_jonam@ yahoo.com >
wrote:
>> it is Ok.. But why that error is not shown for main in first snippet
> Because main has been declared.
> -- Brett
> ------------ --------- --------- --------- --------- --------- -
> "In the rhythm of music a secret is hidden;
> If I were to divulge it, it would overturn the world."
> -- Jelaleddin Rumi
>
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