manoj... you just did someone's homework. I'd hope they'd be satisfied. I've came to an idea. Maybe, if we do their homework for them and add in some odd errors to dock them points, they'll do it themselves, after the first c/d or what ever. <cackle>
Thanks, Tyler Littlefield email: [EMAIL PROTECTED] web: tysdomain-com Visit for quality software and web design. skype: st8amnd2005 ----- Original Message ----- From: Manoj Vivek To: [EMAIL PROTECTED] Cc: [email protected] Sent: Saturday, November 08, 2008 5:53 AM Subject: RE: [c-prog] finding odd element.. this can be solved as follows..... if you consider that the 2n+1 is 11 them we can do the program as follows main() { int a[11],i,j,ans; for(i=0;i<11;i++) scanf("%d",&a[i]); for(i=0;i<11;i++) { for(j=0;j<11;j++) { if(i==j) continue; if(a[i]==a[j] continue; else ans=a[j]; } } printf("%d",ans); } satisfied??? una_020 wrote: > given an array of 2n+1 elemnts n of the elemnts having duplicates how > do u find the number wihout having duplicate..? ? > [Non-text portions of this message have been removed]
