The program is written in C. :) I have the parameters check in my
program already, I'm just struggling with how to write that loop.
char *c = argv[2];
while (*argv[2])
{
if ((isupper(*argv[2])) || (isdigit(*argv[2])))
{ continue; }
else
printf("Second parameter includes forbidden characters");
return EXIT_FAILURE;
}
But that doesn't work.
--- In [email protected], "David Hamill" <[EMAIL PROTECTED]> wrote:
>
> > My program is run in the command line with two parameters:
> >
> > program -param1 param2
>
> This is a C answer, it may be slightly different in C++.
>
> If you declare
>
> int main(int argc, char *argv[])
>
> you should first check that argc == 3 and exit with a
> suitable error message if not. With argc == 3, you can
> access argv[0] (program name), argv[1] (param1 string),
> argv[2] (param2 string).
>
> BTW argc and argv can have any names you like but these are
> the conventional ones (for argument count and argument
> vector).
>
> > I need the program to check if the param2 includes any
> > characters
> > other than capital letters (A-Z) and numbers (0-9).
>
> Loop through argv[2] until you reach the terminating '\0',
> applying the "is" functions of <ctype.h> to each char. Or
> you could do it the long way and compare each char with 'a',
> 'z', '0', '9'.
>
> Good luck!
>
> David
>
