I have tried the same on gcc and does not give any error here also . i
also tried to print the value of i the program while running the
program , i am not an expert , but i suspect the memory allocation after
*i=30 , is not changing , does that have anything to do with the
problem ??
Breakpoint 1, main () at doubt.c:5
5 {
Missing separate debuginfos, use: debuginfo-install glibc.i686
(gdb) print i ;
Invalid character ';' in expression.
(gdb) print i
$1 = (int *) 0x8048450
(gdb) step
main () at doubt.c:7
7 i=(int *)malloc(1*sizeof(int));
(gdb) print i
$2 = (int *) 0xbbddd0
(gdb) step
8 *i=30;
(gdb) print i
$3 = (int *) 0x88c8008
(gdb) step
9 free(i); // freed the mem
(gdb) print i
$4 = (int *) 0x88c8008
(gdb) step
10 *i=50; // Tried to acces it again .. Ideally , it should fail .
But it is not failing .. can any //one explain the reason.
(gdb) print i
$5 = (int *) 0x88c8008
(gdb) step
11 }
(gdb) print i
$6 = (int *) 0x88c8008
(gdb) step
0x00be55d6 in __libc_start_main () from /lib/libc.so.6
(gdb) print i
No symbol "i" in current context.
(gdb) step
Single stepping until exit from function __libc_start_main,
which has no line number information.
Program exited with code 010.
(gdb) print i
No symbol "i" in current context.
On Tue, 2008-11-11 at 00:19 +0530, Gopi Krishna Komanduri wrote:
> Hi All,
> I have a very basic query. I know that after deallocating memory for
> a pointer , when we try to access it , we will get access violation
> error. From top of my memory , even I tried it and worked on it. But
> now I dont know why but my code is working in wrong manner now. Can
> any one of you please suggest it please. I am using VisualStudio 2005
> compiler. on windows xp.
>
> #include<stdio.h>
> #include<malloc.h>
>
> void main()
> {
> int *i;
> i=(int *)malloc(1*sizeof(int));
> *i=30;
> free(i); // freed the mem
> *i=50; // Tried to acces it again .. Ideally , it should fail .
> But it is not failing .. can any //one explain the reason.
> }
>
> Thx,
> --Gopi
>
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