goes into an infinite loop for me too , using gcc 4.3.0
On Mon, 2008-11-10 at 21:48 -0500, Brett McCoy wrote:
> On Mon, Nov 10, 2008 at 9:25 PM, pm rao <[EMAIL PROTECTED]>
> wrote:
>
> > Could you please help me out in analysing this issue:
> >
> > I really find strange behavior with the following code. If the
> > statement b is present as below, the for loop is executing
> infinitely.
> > But when statement b is replaced with statement a as
> > int c[31], s[31];. Then the for loop is exited after n iterations.
> > Below is my gcc version where i executed the code. Please help me
> out
> > in this regard.
>
> Your code executes as expected for me (using gcc under CygWin).
> However, a couple of things to note:
>
> > int c [30], s[30]; // statement b
> >
> > #include <stdio.h>
> > void change (int a[], int, int);
> > int main ()
> > {
> > int d[3];
> > d[0] = 1, d[1] = 10, d[2] = 25;
> > int n = 30, k = 3;
> > change (d, k, n);
> > return 1;
> > }
>
> main() should return 0 on successful completion
>
> > void change (int d[], int k, int n)
> > {
> > int c [30], s[30]; // statement b
> > c[0] = 0;
> > int p;
> > int min, i, coin = 0;
> >
> > for (p=1; p<=n; p++)
>
> Tradtionally, you start a loop on 0 and go to n - 1.
>
> for(p = 0; p < n; p++)
>
> > {
> > c[p] = 0;
> > s[p] = 0;
> > printf ("\n test : %d \n", p);
> > }
> > }
>
> -- Brett
> ----------------------------------------------------------
> "In the rhythm of music a secret is hidden;
> If I were to divulge it, it would overturn the world."
> -- Jelaleddin Rumi
>
>
>
>
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