Hello,
I'm working my way through a book on arithmetic. There is a table of
the numbers from 1 to 99:
1 8 15 22 29 36 43 50
57 64 71 78 85 92 99 6
13 20 27 34 41 48 55 62
69 76 83 90 97 4 11 18
25 32 39 46 53 60 67 74
81 88 95 2 9 16 23 30
37 44 51 58 65 72 79 86
93 7 14 21 28 35 42 49
56 63 70 77 84 91 98 5
12 19 26 33 40 47 54 61
68 75 82 89 96 3 10 17
24 31 38 45 52 59 66 73
80 87 94
the instructions are to work down the columns, not across the
page, answers are given for each exercise. The idea is to practise
addition or multiplication. I wanted to be able to have the solutions
in the form of the original table rather than sequentially. I also
found one error in the answers, so wanted something more reliable. I
have
table1.h:
const int table1[99] = {1,57,13,69,25,81,37,93,56,12,68,24,80,
8,64,20,76,32,88,44,7,63,19,75,31,87,
15,71,27,83,39,95,51,14,70,26,82,38,94,
22,78,34,90,46,2,58,21,77,33,89,45,
29,85,41,97,53,9,65,28,84,40,96,52,
36,92,48,4,60,16,72,35,91,47,3,59,
43,99,55,11,67,23,79,42,98,54,10,66,
50,6,62,18,74,30,86,49,5,61,17,73};
add.c:
#include "table1.h"
#include <stdio.h>
int main(void)
{
int a=17;
int i;
int j;
for (j=0;j<2;j++)
{
for (i=0+j;i<42;i=i+13)
printf("%d\t",table1[i]+a);
for (i=51+j;i<99;i=i+12)
printf("%d\t",table1[i]+a);
printf("\n");
}
for (j=2;j<12;j++)
{
for (i=0+j;i<42+j;i=i+13)
printf("%d\t",table1[i]+a);
for (i=51+j;i<99;i=i+12)
printf("%d\t",table1[i]+a);
printf("\n");
}
printf("%d\t%d\t%d\n",table1[12]+a,table1[25]+a,table1[38]+a);
return 0;
}
multiply.c is the same as add.c, except the operation is different.
was there a less torturous way of doing this (ignoring the obvious flaw
of having to recompile for every new question)?
Rick
