--- In [email protected], Praveen S <mailprave...@...> wrote: > I have a executable file at a particular location in the filesystem. From > root directory i run this exe. This exe will load a shared object from > another location (say /usr/lib). Now the shared object wants to read a > config file which is in the directory where the exe is located. How can it > get that path.
See here for an example of how to get executable location on windows, linux, solaris and os-x (each platform is different): http://svn.codehaus.org/groovy/trunk/groovy/modules/native_launcher/ source/jst_fileutils.c Look for function called getExecutableHome Consider at least twice before resorting to using this - it may create security problems if the executable is run w/ higher privileges than the user running it has. It is easy for the user to twist the executable location into something different by e.g. creating a hard link to the executable and running the program via that (the location of the hard link will show as the exec location) and that way make the app load whatever he provides. On *nixes you can often rely on "well known locations", i.e. hard code the location to the binary at compile time and just assume the stuff you need is there. ::Antti::
