--- In c-prog@yahoogroups.com, Rick <mowgl...@...> wrote:
>
> >My code is clearer and has
> >a touch of elegance, vis-à-vis the bitwise operator.
>
> I don't see two strings, only one. Can you explain the "two strings" comment?
...and also why using the bitwise operator in your code gives it a touch of
elegance ie. why is this:
if (!f1 & !f2) f1=f2=1;
more elegant than:
if (!f1 && !f2) f1=f2=1;
? As far as I can tell they both give the same result, although the && might be
more efficient because if !f1 is 0 then !f2 won't be evaluated. Using &, !f2
will always be evaluated (unless optimised out somehow?).
Also, you are mixing logical (!) and bitwise (&) operators, which I would argue
makes the code less clear - it looks like a bug. If you run the code through
Gimpel's excellent PC/Flexe-Lint utility, you get:
if (!f1 & !f2)
Warning 514: Unusual use of a Boolean expression
