Anup,
The code of my friend has superfluous statements.
Try this, shorter and faster:
int greater(int a, int b) {
int result=b; // (1)
(a>b) && (result=a); // (2)
return result;
}
(1) I suppose it's b.
(2) If a>b, the testing cannot be logically predicted yet, is not
short-circuited and result is a; otherwise (if not a>b), the testing can
already be logically predicted (with &&, one negative is enough), is
short-circuited and result is already known.
And to work out the lesser:
int lesser(int a, int b) {
int result=b; // (1)
(a>b) || (result=a); // (2)
return result;
}
(1) I suppose it's b.
(2) If a>b, the testing can already be logically predicted (with ||, one
positive is enough), is short-circuited and result is already known; otherwise
(if not a>b), the testing cannot be logically predicted yet, is not
short-circuited and result is a;
Good results!
Geraldo
--- In [email protected], Anup Joshi <joshian...@...> wrote:
>
> Hello friends,
> I wanted to find biggest number of given two numbers without using the
> loop statement, the if-conditional, or the ternary operator ?:. One way
> i could do this was with the following code:
>
> int biggest(int a, int b) {
> int result;
>
> (a<b) && (result = b); // b is bigger
> (a>b) && (result =a); // a is bigger
> (a==b) && (result = a) // both are equal
>
> return result;
> }
>
> this code works for positive as well as negative ints.
> i wanted to know if there was any other way to find the biggest number
> of the two, by using any other c operator or snippet.
>
> Thanks & Regards :-)
>
> anup
>
