hi,
im having trouble tryng to pass my array into a function. so here is the deal.
i
made an array of let say unsigned char. but i dont know the size of the array,
so i just put it as a pointer. then i send this pointer to a function that will
fill the array with known size. offcourse after it set the size of the pointer.
after the method called, i want the pointer that i just created before is the
array that filled. basically the code is like this:
using namespace std;
void testArray(unsigned char** array) {
*array = (unsigned char*)malloc(3);
assert(*array);
*array[0] = 'a';
*array[1] = 'b';
*array[2] = 'd';
}
int main ()
{
unsigned char * array;
testArray(&array);
std::cout << array[0];
}
but its not working. when i try to fill the array, it gives me error bad access
or something.
if i do it as an ordinary array:
void testArray(int* array) {
array = new int[3];
array[0] = 1;
array[1] = 2;
array[2] = 3;
}
int main ()
{
int * array;
testArray(array);
std::cout << array[0];
}
it prints the wrong value: -1073743920, which is i think is an
adress, -1073743920.
is there a way to get send a pointer as a reference, set as an array in the
function, and then called later on the main function?
thanks in advance. =================================
http://www.svnstrk.blogspot.com
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