If you're trying to serialize a document to a string, why not use DOMWriter::writeToString()?
-----Original Message----- From: Nuno Ferreira [mailto:[EMAIL PROTECTED] Sent: Monday, April 28, 2008 1:26 PM To: [email protected] Subject: Re: How to know a node position in the tree Imagining that some info might be not present, like in the following example, Michael has no age Example: <population> <person> <name>John</name> <age>54</age> </person> <person> <name>Michael</name> </person> </population> I want to write the previous XML to a continuous string: char* xml = "<population><person><name>John</name><age>54</age></person><person><nam e>Michael</name></person></population>" since i'm reading the XML file from the top i get: field name: population ; field value: field name: person ; field value: field name: name ; field value: John field name: age ; field value: 54 field name: person ; field value: field name: name ; field value: Michael What i need to know is that after the age from John, i need to close the tag person </person> and open a new one <person>... Since the age might be not present, the closing tag </person> might come after the </name> tag. This is why i'm asking if there is a way to know if the tag i'm reading now is in a different depth in the tree compared to the previous tag. If this is not possible, you are welcome to suggest other approaches :-) Thank you On Thu, Apr 24, 2008 at 5:16 PM, Jesse Pelton <[EMAIL PROTECTED]> wrote: > I'm going to make a wild guess that you're looking for, say, <name> > elements in the document, then processing them. Then you do the same > thing for <age> elements, and you need to make sure that "John" ends up > with an age of "54" and not some other age. > > If that's the case, I think you need to invert your processing model. > Instead of searching for <name> and <age> elements, look for <person> > elements and process the children of each one. All the children of a > given <person> element will relate to the same person if your documents > are rational. > > If I'm off base, maybe you should send a short code sample that > demonstrates what you're trying to do. > > -----Original Message----- > From: Nuno Ferreira [mailto:[EMAIL PROTECTED] > Sent: Thursday, April 24, 2008 11:40 AM > To: [email protected] > Subject: Re: How to know a node position in the tree > > Hi, > > i'm using DOM and XPath from Xerces 3.0.0b > Basically in the following example, I want to know that after the <age> > tag, > this person info is over and another one might come next. So i have to > know > that the second <person> tag comes first in the tree compared to <name> > or > <age>. > > Hope i made myself clear this time. > Thanks. > > <population> > <person> > <name>John</name> > <age>54</age> > </person> > <person> > (...) > </person> > </population> > > On Fri, Apr 18, 2008 at 12:39 PM, Jesse Pelton <[EMAIL PROTECTED]> wrote: > > > I think you'll need to say a little more. Are you using DOM or SAX? > > What do you mean by "one level behind?" Do you want to know if one > node > > is the parent of another? > > > > -----Original Message----- > > From: Nuno Ferreira [mailto:[EMAIL PROTECTED] > > Sent: Wednesday, April 16, 2008 2:40 PM > > To: [email protected] > > Subject: How to know a node position in the tree > > > > I tried a couple of tricks to see if a node is positioned one level > > behind > > in the tree but none of them worked. > > > > How to check if the current node is one level behind in the tree > > compared to > > the previous one? > > > > > > Thank you. > > >
