try
function copytest($id)
{
$this->Applicant->id = $id;
$this->data = $this->Applicant->read();
$this->Applicant->id = null;
unset($this->data['Applicant']['id']);
$this->data['Applicant']['schoolyear_id'] = 16;
$this->Applicant->save($this->data['Applicant']);
}
or what I usually do
function copytest($id)
{
$this->Applicant->id = $id;
$this->data = $this->Applicant->read();
$this->Applicant->create(); // create a new record for saving
unset($this->data['Applicant']['id']);
$this->data['Applicant']['schoolyear_id'] = 16;
$this->Applicant->save($this->data['Applicant']);
}
HTH
sdevore
On 9/15/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
>
> Thanks for the reply.
>
> I tried unsetting the 'id' value, but most strangely, the result is
> that it changes the original record anyway!
>
> I've tried it a dozen times, just to make sure, but that is indeed what
> is happening.
>
> function copytest($id)
> {
> $this->Applicant->id = $id;
> $this->data = $this->Applicant->read();
> unset($this->data['Applicant']['id']);
> $this->data['Applicant']['schoolyear_id'] = 16;
>
> $this->Applicant->save($this->data['Applicant']);
> }
>
>
> If I pass it $id = 1, then it modifies record 1 in the database and
> sets the schoolyear = 16.
>
> If instead, I use this code:
>
> function copytest($id)
> {
> $this->Applicant->id = $id;
> $this->data = $this->Applicant->read();
> $this->data['Applicant']['id'] = null;
> $this->data['Applicant']['schoolyear_id'] = 16;
>
> $this->Applicant->save($this->data['Applicant']);
> }
>
>
> It leaves record 1 alone, and creates a copy into record 2 with
> schoolyear = 16 -- which is exactly what I want, EXCEPT that it also
> creates copies into record 3 and record 4, both with schoolyear = 16 as
> well.
>
> Any ideas?
>
>
> >
>
--
==
S. DeVore
(the old fart) the advice is free, the lack of crankiness will cost you
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