you're right,there is an array of users ($users), but I'm afraid I
haven't explained myself well, what I'd like to know is if it's
possible to display a constant string using input()? because every-
time I try to do this, the string is displayed, but as a label.
P.S. I did try what you told me about placing array('type' => 'text')
as the
second argument of the input method, but it only forces the control to
be a input text
On 11 mayo, 20:38, Miles J <[email protected]> wrote:
> Theres some magic that happens. If you have an ID field (user_id), it
> will usually be a select. If you set a variable called $users to the
> view, that input field will populate with that data.
>
> You can overwrite that by just placing array('type' => 'text') as the
> second argument of the input method.
>
> On May 11, 10:54 am, Alonso <[email protected]> wrote:
>
>
>
>
>
>
>
> > Hi, folks.
> > I'm starting with CakePHP and after reviewing this tutorial
> > (http://book.cakephp.org/view/1543/Simple-Acl-controlled-Application
> > ) and also after having used the "cake bake" command to generate my
> > models,
> > controllers and views , everything is fine, but when I visit the
> > Post's add view (views \ posts
> > \ add.php), I find that instead of showing a input text for the
> > username, it shows a select with all the usernames.
>
> > this is the line in the Post's add view that show the select.
>
> > echo $this->Form->input('user_id');
>
> > Although I know how to display only the username of the currently
> > logged-in user, I don't know how to control the content to show in
> > $this->Form->input() because if I use a variable that is not part of
> > the "Post" model , it's shown , but as the label for the input.
>
> > Have you any idea how to solve this??
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