I've been poking around with this for a bit and have yet to find out what's
going wrong. I'm passing a paginated result set to a view and everything
renders fine until I try to access the next page of results.
Example:
// CONTROLLER //
$this->paginate = array(
'contain' => array(
'OnlineUser',
'Seeking',
'UserProfile' => array('conditions' => array('UserProfile.order' => 1)),
'Score' ,
'Photo' => array('conditions' => array('Photo.profile' => 1),
'limit' => 1,
'fields' => 'name'
)
),
'conditions' => array(
'Seeking.orientation' => $orientation,
'User.gender' => $gender,
'User.age BETWEEN ? AND ?' => array($minAge, $maxAge),
'User.country' => $country,
'User.region' => $region,
'NOT' => array(
' User.id' => array(2, $this->Auth->User('id'))),
'AND' => array($seekingOption)
),
'limit' => 5,
'order' => 'last_login DESC'
);
$user = $this->paginate('User');
$this->set(compact('user''));
// VIEW //
<div class="paging">
<?php echo $this->Paginator->prev('<< ' . __('previous', true), array(),
null, array('class'=>'disabled'));?>
<?php echo $this->Paginator->numbers();?> |
<?php echo $this->Paginator->next(__('next', true) . ' >>', array(), null,
array('class' => 'disabled'));?>
</div>
I debugged $this->Paginator and everything seems to be in place just as I
would expect and the first 5 results of the set render just fine in the view
also as expected. Nothing seems out of place with the Pagination in the
initial view ... the links generated by $this->Paginator->numbers() and
$this->Paginator->next() are correct and clicking them loads the appropriate
controller/action ... ie. /controller/action/page:2. This is the point where
it starts throwing errors. The view is complaining about "undefined
variable", "invalid argument supplied for foreach()", "undefined property
View::Paginator" ... pretty much everything you would expect if no data were
being passed to the view. I'll also add that the pagination works just as it
should everywhere else throughout the app with no issues.
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