Hi people, I´m from Venezuela sorry my english.

I have a little problem and I need your help

I need to work with Jquery Easy UI (http://www.jeasyui.com) and with
Cakephp together.

But I can´t do it work.

I make the query in the controller and return the data in Json format:

 function getPaises(){
        $this->autoRender= false;
        Configure::write('debug', 0);

        $paises = $this->Pais->find(
            'all',
            array(
                'fields'=>array(
                    'Pais.id',
                    'Pais.nombre'
                )
            )
        );

        return (json_encode($paises));
    }

In view, I have:

<table id="tt"></table>


<input type="hidden" id="url-listado-paises" value="<?php echo $this-
>Html->url(array('controller'=>'paises','action'=>'getPaises')); ?>"/>

<script>
    $('#tt').datagrid({
        url:$('#url-listado-paises').val(),
        columns:[[
            {
                'Pais': {
                    field:'id',title:'ID',width:100,
                    field:'nombre','title':'Nombre'
                }
            }
        ]]
    });
</script>

But it doesn´t work

Any idea why?

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