Hi people, I´m from Venezuela sorry my english. I have a little problem and I need your help
I need to work with Jquery Easy UI (http://www.jeasyui.com) and with Cakephp together. But I can´t do it work. I make the query in the controller and return the data in Json format: function getPaises(){ $this->autoRender= false; Configure::write('debug', 0); $paises = $this->Pais->find( 'all', array( 'fields'=>array( 'Pais.id', 'Pais.nombre' ) ) ); return (json_encode($paises)); } In view, I have: <table id="tt"></table> <input type="hidden" id="url-listado-paises" value="<?php echo $this- >Html->url(array('controller'=>'paises','action'=>'getPaises')); ?>"/> <script> $('#tt').datagrid({ url:$('#url-listado-paises').val(), columns:[[ { 'Pais': { field:'id',title:'ID',width:100, field:'nombre','title':'Nombre' } } ]] }); </script> But it doesn´t work Any idea why? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/cake-php
