can you translate this to english?what is maak?
On Saturday, June 9, 2007 5:01:29 PM UTC+8, Watcher wrote:
>
> This is how I fixed this kind of thing:
>
> Model:
> class Menu extends AppModel {
> var $name = 'Menu';
>
> // model validation
> var $validate = array(
> 'naam' => VALID_NOT_EMPTY, //
> backwards compatible
> );
>
> function maakMenu($belongs_id = '0') {
> $menu_voor_view = array();
> $menuitems = $this->findAll("belongs_to = '$belongs_id'",
> '',
> 'Menu.zwaarte ASC');
> foreach($menuitems as $item) {
> $item = $item['Menu'];
> if ($item['url'] == '') {
> $submenu = $this->maakMenu($item['id']);
> $menu_voor_view[$item['naam']] = $submenu;
> } else if ($item['sub'] == '1') {
> $submenu = $this->maakMenu($item['id']);
> $menu_voor_view[$item['naam']] =
> $item['url'];
> $menu_voor_view[$item['naam'].'.sub'] =
> $submenu;
> } else {
> $menu_voor_view[$item['naam']] =
> $item['url'];
> }
> }
> return $menu_voor_view;
> }
> }
>
> $menu_voor_view = array to return
> naam = link name
> submenu = int to indicate if this menu has submenu's or not, so as to
> allow a topcategory to have a url and subitems (it normally assumes
> that if no url is there, it must have a submenu)
> belongs_to = id of topcategory
> zwaarte = shows the location of a specific menu in the list of all
>
> Controller:
> class MenuController extends AppController {
> var $name = 'Menu';
>
> function maakMenu($belongs_to = '0') {
> if (isset($this->params['requested'])) {
> $menu = $this->Menu->maakMenu($belongs_to);
> return $menu;
> } else {
> $this->redirect('/');
> }
> }
> }
>
> this just returns the menu array made in the model (and as it is
> recursive there, it returns a complete menu array)
>
> To include a menu on a view, I created an element and that is
> rendered:
> $menu = $this->requestAction('menu/maakMenu');
>
> function printSubMenu($submenu, $html, $eerste) {
> print '<ul';
> if ($eerste) {
> print ' id="nav"';
> }
> print '>';
>
> foreach($submenu as $naam => $url) {
> // checking for submenu
> if (!ereg('.*\.sub', $naam)) {
> print '<li>';
> if (is_array($url)) {
> echo $html->link($naam, '#');
> printSubMenu($url, $html, false);
> } else if (isset($submenu[$naam.'.sub'])) {
> echo $html->link($naam, '#');
> printSubMenu($submenu[$naam.'.sub'],
> $html, false);
> } else {
> echo $html->link($naam, $url);
> }
> print '</li>';
> }
> }
> }
>
> // $html is needed to use the $html helper functions!
> printSubMenu($menu, $html, true);
>
>
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