render your template with $this->render(); and pass variables to it, than
here just print json_encode($variable); :)
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2012/10/31 Jeremy Burns | Class Outfit <[email protected]>

> Completely - but how do I render the element as json? As soon as I do
> $this->render('/elements/whatever'); it's returned as straightforward html.
>
> Jeremy Burns
> Class Outfit
>
> http://www.classoutfit.com
>
> On 31 Oct 2012, at 15:28:01, Tilen Majerle <[email protected]>
> wrote:
>
> in both cases return json value and have keys eg. "success" (true/false)
> and "data". If "success" == true, just "print" data, if "success" == false,
> than use data as json, and decode that string and print validation errors,
> or generate string in controller for errors and print it..understand ?
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>
>
> 2012/10/31 Jeremy Burns <[email protected]>
>
>> Not an expert at jQuery, but getting there.
>>
>> I'm submitting data to a controller function that saves a record via
>> ajax. If the save works, I'm rendering an element, which then appears back
>> in the ajax form as html ready to be placed into a dom element. All good -
>> that works fine. But if the save fails I want to return an array that
>> includes the validation errors - that really ought to be json. So on
>> success I want html, on error I want json - and I can't have both.
>>
>> How do I either (i) render the element but have it returned as json (and
>> ideally tack in a 'success' key that I can check in the jQuery) or (ii)
>> otherwise determine the success/error state when html has been returned to
>> the jQuery?
>>
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