Hi
I'm using PHP to create forms for user to fill up. part of the form is not
for everyone, so users who want to fill it up has to click on a box below
the form to trigger new fields. I'm using Ajax for triggering the hidden
part of the forms. Ajax will make a new part of the form apear in the page
without having to refresh.
The problem is that when I trigger several of the hidden parts I can submit
them all to the data base at once. each of them was triggered at a
different time and it has its own save button.
How can I save them at once.
"Proprofs" quiz making site is a good example. user can add different type
of questions as he goes in making a quize the different questions for will
appear on the page then will be submitted at once.
Ajax code.
function handleChange(cb) {
//get the selected value
var value = cb.value;
var divNum = cb.value;
//status variable for validation
var status;
(cb.value == 0 )?status ='new': status =2;
alert (cb.value);
//set image back to delete and undo deletion
if (cb.name =='undo')
status='delete';
if (cb.value==0)
//check if browser suports ajax
var xmlhttp = null;
if(typeof XMLHttpRequest != 'udefined'){
xmlhttp = new XMLHttpRequest();
}
else if(typeof ActiveXObject != 'undefined'){
xmlhttp = new ActiveXObject('Microsoft.XMLHTTP');
}
else
throw new Error('You browser doesn\'t support ajax');
//open connection with activateImages.php to recieve the active images as
an acho
xmlhttp.open("GET", "ManageQuestionsImages.php?status="+status +
"&id="+value,true);
if (status !='new'){
//check if ready to recieve
xmlhttp.onreadystatechange = function (){
if(xmlhttp.readyState == 4)
window.activate(xmlhttp,divNum);
};
xmlhttp.send(null);
}
else {
//check if ready to recieve for add new template form
xmlhttp.onreadystatechange = function (){
if(xmlhttp.readyState == 4)
window.activated(xmlhttp);
};
xmlhttp.send(null);
}
}
//recieve the active images then insert them in the specified location of
the page.
function activate(xhr,divNum){
if(xhr.status == 200){
document.getElementById(divNum).innerHTML = xhr.responseText;
}
else
throw new Error('Server has encountered an error\n'+
'Error code = '+xhr.status);
};
//recieve the active form then insert it in template div.
function activated(xhr){
if(xhr.status == 200){
document.getElementById('template').innerHTML = xhr.responseText;
}
else
throw new Error('Server has encountered an error\n'+
'Error code = '+xhr.status);
}
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