hi cricket,...
I did manage that, and the code is slightly different from above,... In my
case,... and here is the code if anyone needs it:
<script type="text/javascript">
$(document).ready(function() {
$('#photo_comments_dialog_<?php echo $photo_comment['PhotoComment']['id']
?> a').each(function() {
var $link = $(this);
var $dialog = $('<div></div>')
.load($link.attr('href'))
.dialog({
autoOpen: false,
width: 500,
modal: true,
title: 'Report Photo Comment',
});
$link.click(function() {
$dialog.dialog('open');
return false;
});
});
});
</script>
and the link:
<div id="photo_comments_dialog_<?php echo
$photo_comment['PhotoComment']['id'] ?>"><?php echo
$html->link(__('report', true), '/report/photo_comment/' .
$photo_comment['PhotoComment']['id'], array('class' => 'report')) ?></div>
thank You guys All !
Salute,
chris
On Saturday, March 9, 2013 3:11:24 PM UTC-8, cricket wrote:
>
> You're getting a new window because your link's click event has
> window.open() attached to it.
>
> What does this have to do with CakePHP, anyway?
>
> On Sat, Mar 9, 2013 at 4:33 PM, Chris <[email protected] <javascript:>>
> wrote:
> > hi there,… can you help me please,…
> > I’m trying to load dialog page, but instead I’m getting new window
> popup,…
> > how can I accomplish this,…?
> >
> > hi guys,... can anyone help,...?
> > this is what I got so far,... I'm trying to load jquery dialog page, but
> > instead I'm getting new window popup,... how can I accomplish this,...?
> >
> > <script>
> > $(document).ready(function() {
> > $('#photo_comments_opener_<?php echo
> $photo_comment['PhotoComment']['id']
> > ?>').each(function() {
> > var $link = $(this);
> > var $dialog = $('<div></div>')
> > .load($link.attr('href') + ' #content')
> > .dialog({
> > autoOpen: false,
> > title: $link.attr('title'),
> > width: 500,
> > height: 300
> > });
> >
> > $link.click(function() {
> > $dialog.dialog('open');
> >
> > return false;
> > });
> > });
> >
> > });
> > </script>
> >
> > and here is the link:
> >
> > <?php echo $html->link(__('report/spam', true), '/report/photo_comment/'
> .
> > $photo_comment['PhotoComment']['id'], array('id' =>
> > "photo_comments_opener_".$photo_comment['PhotoComment']['id'], 'class'
> =>
> > 'report', 'onclick' => "window.open(this.href, 'popupwindow',
> 'width=500,
> > height=300'); return false;")) ?>
> >
> > thanks in advance
> > chris
> >
> >
> > On Thursday, March 7, 2013 5:23:46 PM UTC-8, Chris wrote:
> >>
> >> hi guys,... can anyone help please ,...
> >> how can I call content from another page into a dialog box without
> >> remoteFunction,... any other way,...?
> >>
> >> <script type="text/javascript">
> >> <?php echo $ajax->remoteFunction(array('url' => array('controller' =>
> >> 'photo_comment', 'action' => 'report_spam/',
> >> $photo_comment['PhotoComment']['id']), 'update' =>
> >> "photo_comments_reports_".$photo_comment['PhotoComment']['id'] )); ?>
> >> </script>
> >> this is what I currently have,... but it's conflicting with
> remoteFunction
> >> in remoteFunction page.
> >>
> >> thanks in advance
> >> chris
> >>
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