Here's what I am trying to accomplish: A user fills out a form, saves a record. At some later date they wish to "clone" this record, but may want to make a few tweaks. This "clone" functionality should direct them to a form that is pre-filled with the previous record's data so that they can review it, edit as needed, and submit it as a new record.
What I'm trying: I've modified my add() function to accept a parameters: function add($cloneid = NULL) Then created a Clone link that sends them to <site>/model/add/<id> Then, I get the data from that model: $clone_source = $this->Model->findById($cloneid); $this->data['Model']['field1'] = $clone_source['Model']['field1']; and so on. Based on Google searching and other posts, this should work. But what actually happens is that upon clicking the 'Clone' link, the user is directed and the form submits itself immediately (failing to save the record, since it fails validation) and the user never actually sees the form. What am I doing wrong? (Also I should note, there are relational models present, but I don't think this should be the cause of any problems...I hope). -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
