It looks like `Controller::render()` sets the body on the CakeResponse
object and then returns the CakeResponse
object: http://api.cakephp.org/2.6/source-class-Controller.html#922-962. I
would imagine you could access the rendered view like so:
public function test()
{
$this->render('/Emails/html/test', false);
$emailBody = $this->response->body;
// Do what you want with $emailBody here
}
On Wednesday, February 4, 2015 at 5:33:35 PM UTC-5, BrendonKoz wrote:
>
> For various reasons I had decided to use a 3rd party email library within
> my current CakePHP project. I thought that it might be nice to use
> CakePHP's Views to create templating for my emails and take advantage of
> layouts too. Unfortunately I'm stumped on just how to retrieve the rendered
> output of a view back to the Controller method.
>
> I've tried the following:
>
> public function test() {
> $this->layout = false;
> #$this->view = '/Emails/html/test.ctp';
> $var = $this->render('/Emails/html/test', false);
> pr($var->_body); die();
> }
>
> $var->_body is protected (as denoted by the underscore). I saw no other
> property within the $var variable that contained the "body" code within my
> (template) view.
>
> Are there any ways to do this that I'm just not seeing? If so, can I
> safely presume that layouts would be handled in a similar fashion?
>
> Thank you for any possible help...
>
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