Try
function search()
{
if (!empty($this->data))
{
$search_term = $this->data['Candidato']['nome'];
$conditions = array(
'Candidato.nome' => "LIKE %{$search_term}%"
);
$results = $this->Candadato->findAll($conditions);
$this->set('candidatos', $results);
$this->render('index');
}
}
-MI
---------------------------------------------------------------------------
Remember, smart coders answer ten questions for every question they ask.
So be smart, be cool, and share your knowledge.
BAKE ON!
blog: http://www.MarianoIglesias.com.ar
-----Mensaje original-----
De: [email protected] [mailto:[EMAIL PROTECTED] En nombre
de Norman
Enviado el: Lunes, 26 de Febrero de 2007 07:28 p.m.
Para: Cake PHP
Asunto: Ambiguous columns in findAll()
The problem is, when the model have any relation with another table/
model which contains an ambiguous field name, this method fails with
SQL errors: "SQL Error in model Candidato: 1052: Column 'nome' in
where clause is ambiguous".
Is there any way I can avoid this? Recursion = 0 stopped the SQL
errors, but then findAll() returns no results.
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