there is a queryCache feature
On 16 mar, 17:34, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote:
> Guys I already tried those changes, whether I add $this->Project->id
> and $this->Project->read(null,$id) , still have the same problem
>
> On Mar 16, 6:55 am, "GMail" <[EMAIL PROTECTED]> wrote:
>
> > I think you have a typo
>
> > function admin_toggleactive($id = null){
>
> > if (!$id) return;
>
> > $this->layout = 'ajax';
> > $this->autoRender = false;
>
> > $this->Project->id = $id; // And not $this->id = $id
>
> > $project = $this->Project->read();
>
> > > -----Messaggio originale-----
> > > Da: [email protected]
> > > [mailto:[EMAIL PROTECTED] Per conto di [EMAIL PROTECTED]
> > > Inviato: venerdì 16 marzo 2007 7.44
> > > A: Cake PHP
> > > Oggetto: savefield woes
>
> > > Quick question:
>
> > > I have this function to toggle an 'active' field un a project model,
>
> > > function admin_toggleactive($id = null){
>
> > > $this->layout = 'ajax';
> > > $this->autoRender = false;
>
> > > if ($id) {
> > > $this->id = $id;
> > > }
> > > if (!$this->id) return;
>
> > > $project = $this->Project->read();
> > > if($project['Project']['active']=='1'){
> > > $this->Project->saveField('active','0');
> > > }
> > > else{
> > > $this->Project->saveField('active','1');
> > > }
>
> > > $this->data = $this->Project->read();
> > > $this->render('../elements/project_set_unset_active');
>
> > > }
>
> > > Now this wont work, the data returned to the element is the
> > > same data (without the field toggled). BUT if I replace this line
>
> > > $this->data = $this->Project->read();
>
> > > to
>
> > > $this->data = $this->Project->findById($id);
>
> > > the element will be rendered with the new data (the actual
> > > value of the toggled field).
>
> > > Why does this happen ? Is this the only way to work around this?
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