Sorry, I forget this :
$val = Javascript->escapeString($this->renderElement(..));
$js = "new Insertion.Bottom('data', $val')";
That should be better
On Jun 14, 5:50 pm, francky06l <[EMAIL PROTECTED]> wrote:
> The problem concerning the renderElement, might be due to the content
> of your rendered element (the style as well).
> try to tace the value rendered by "renderElement" maybe you will find
> the solution.
>
> PS : your thread is still there
>
> For the style, be sure you apply it to the div you update
>
> On Jun 14, 5:31 pm, Dustin Weber <[EMAIL PROTECTED]> wrote:
>
> > Somehow, this question never made it to my previous post [http://
> > groups.google.com/group/cake-php/browse_thread/thread/45442ab30ec579b/
> > 6378626e3a27701e#6378626e3a27701e]. It's like the Google Group lost
> > my post, so I apologize if this shows up twice.
>
> > After a little bit of work and help from francky06l here in the Google
> > Group, I am now appending data to a div that has data in it already.
> > Let me show the basic code so everyone knows what's going on:
>
> > -----------------------------------------------------------------------
> > /** main template code **/
>
> > <?php foreach ($tests as $test): ?>
> > <?php echo $ajax->link("Add More Tests", "/tests/ajaxAddTest/
> > {$id]}",
> > array('update'=>'newData')); ?>
> > <?php endforeach; ?>
>
> > <div id="originalData">existing data here</div>
> > <div id="newData"></div
>
> > /** END main template code **/
> > -----------------------------------------------------------------------
> > /** example ajax_add_test.thtml view **/
> > <?php
> > $ajax->div('dataControl');
> > $data = $this->renderElement('elem_add_test', array('form' =>
> > $form));
> > $js = "new Insertion.Bottom('data', $data)";
> > echo $javascript->codeBlock($js, false);
> > $ajax->divEnd('dataControl');
> > ?>
> > /** END ajax_add_test.thtml view**/
> > -----------------------------------------------------------------------
> > /** example elem_add_test.thtml **/
> > <?php if (!empty($form)) { ?>
> > <?php foreach ($form['Field'] as $field): ?>
> > <?php echo $html->input('Form/field'. $field['id']); ?>
> > <?php endforeach; ?>
> > <?php } ?>
> > /** END elem_add_test.thtml**/
> > -----------------------------------------------------------------------
>
> > Ok, so what I'm doing is this: When the user clicks on the ajax link
> > in the main template, the controller action (ajaxAddTest) does some
> > work, sets the $form array, and renders ajax_add_test.thtml. As you
> > can see in ajax_add_test, I'm don't want to overwrite the data in the
> > newData div, I simply want to append new data into it, keeping the old
> > data.
>
> > So, I go and render an element (elem_add_test.thtml) passing in the
> > $form. I then take the result of that element render and pass it into
> > the javascript code block to append.
>
> > There are two problems I'm having.
>
> > #1) The data overwrites the newData div each time instead of appending
> > to it. If I change the ajax_add_test view to the following code
> > snippet (not using an element), the text NEW TEST DATA appends
> > properly, never overwriting what was in the newData div.
>
> > /** example ajax_add_test.thtml view **/
> > <?php
> > $ajax->div('dataControl');
> > $js = "new Insertion.Bottom('data', 'NEW TEST DATA <br>')";
> > echo $javascript->codeBlock($js, false);
> > $ajax->divEnd('dataControl');
> > ?>
> > /** END ajax_add_test.thtml view**/
>
> > Any suggestions or alternate ways to achieve this update process to a
> > div?
>
> > #2) The rendered elements populated into the newData div never seem to
> > have any style. They lose all the styling applied elsewhere on the
> > site. This a large stumbling block that I need to solve somehow.
>
> > Any help would be greatly appreciated!
>
> > Dustin WeberThe
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