$layout = $this->layout;
$this->layout = null;
$this->render("view_name");
$this->layout = $layout;Geoff -- http://lemoncake.wordpress.com On Jul 5, 5:26 am, Contrid <[EMAIL PROTECTED]> wrote: > Thanks for the responses guys! Greatly appreciated! > > I could use the 'ajax' feature... > But the problem is that I'll then need the Scriptaculous libraries > included. > I don't want that, since I already have jQuery integrated. > How can I make jQuery work with this? > > Best, > > On Jul 4, 8:00 pm, "[EMAIL PROTECTED]" > > <[EMAIL PROTECTED]> wrote: > > All you need to do is type $this->render('view_name','ajax'); > > > ajax is a layout which just contains <?php echo $content_for_layout; ? > > > > without all the usual layout.ctp stuff. > > > this also follows if for whatever reason you need to change the > > layout. (checkout the manual page on controllers for how render works) > > > Simon > > > On Jul 4, 5:07 pm, Contrid <[EMAIL PROTECTED]> wrote: > > > > Hi there, > > > > Within my current view, I want to include another view. > > > I tried using : > > > > <?= $this -> render('view_name'); ?> > > > > ...but it renders the entire layout. > > > I just want the content inside of the view file. > > > > How can I accomplish this? > > > Thank you for your help. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Cake PHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
